Esercitazione 2 canova elt

12
Electrical Basics Course Prof. Aldo Canova  Electrical Basic Course Exercise 2 1) Equivalent resistance 2) One source generator resistive networ k

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Electrical Basics Course Prof. Aldo Canova

Electrical Basic Course

Exercise 2

1) Equivalent resistance2) One source generator resistive network

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Electrical Basics Course Prof. Aldo Canova

Exercise 1

AR1 R2

R

R1=3 [Ω]R2=7.5 [Ω]

=

B

3

R5R6

R4=10 [Ω]R5=5 [Ω]R6=3 [Ω]

RAB?

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Electrical Basics Course Prof. Aldo Canova

A

R1

R3

R2//4

A

R1 R2//4

BR56

R R R

R R2 4

2 4

2 4

7 5 10

7 5 10 4 28 / /

.

. .=+

=

+= Ω

BR3+5R6

R R R3 5 3 5 8 5 13+ = + = + = Ω

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Electrical Basics Course Prof. Aldo Canova

A

B

R1 R(2//4)//(3+5)

R6

( ) ( ) [ ]Ω=+

⋅=

+=

+

+

+ 22.3

1328.4

1328.4

534 // 2

534 // 2

53 // 4 // 2 R R

R R R

( ) ( ) [ ]Ω=++=++= + 22.9322.33653 // 4 // 21 R R R R AB

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Electrical Basics Course Prof. Aldo Canova

R7

t2

Exercise 2 Calculate RAB:a) t1 open and t2 openb) t1 open and t2 closedc) t1 closed e t2 opend) t1 closed e t2 closed

R1=10 [Ω]R2=7.5 [Ω]R3=15 Ω

A

B

1

R2

4

R3

R5R6

t1

R4=18 [Ω]R5=3 [Ω]R6=8 [Ω]R7=10 [Ω]

Resultsa) RAB=13.16 [Ω]b) RAB=11.52 [Ω]c) RAB=12.81 [Ω ]d) RAB=10 [Ω]

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Electrical Basics Course Prof. Aldo Canova

A

R2R1

Calculate RAB:a) t1 open and t2 openb) t1 open and t2 closedc) t1 closed e t2 opend) t1 closed e t2 closed

R1=8 [Ω]R2=13 [Ω]R3=18 Ω

Exercise 3

B

R5 R4 t1

R3

t2

R4=6 [Ω]R5=10 [Ω]

Resultsa) RAB=15.49 [Ω]b) RAB=5.98 [Ω]c) RAB=14.95 [Ω ]d) RAB=4.95 [Ω]

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Electrical Basics Course Prof. Aldo Canova

t2

Exercise 4 Calculate RAB:a) t1 open and t2 openb) t1 open and t2 closedc) t1 closed e t2 opend) t1 closed e t2 closed

R1=10 [Ω]

A B1 2 3

t1

=R3=8 [Ω]

Resultsa) RAB=33 [Ω]b) RAB=10 [Ω]c) RAB=8 [Ω ]d) RAB=3.42 [Ω]

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Electrical Basics Course Prof. Aldo Canova

Exercise 5: One source generator circuit

+

R R R1 4 5

E

A D

E = 48 VR1 = 1 ΩR2 = 80 ΩR3 = 80 ΩR4 = 4 Ω

Evaluate all the current by using voltage and current divider

R2 3 6 7

B C

R5 = 3Ω

R6 = 3 ΩR7 = 1 Ω

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Electrical Basics Course Prof. Aldo Canova

Exercise 5: One source generator circuit

E = 48 VR1 = 1 Ω

R2 = 80 ΩR3 = 80 ΩR4 = 4 ΩR5 = 3 ΩR6 = 3 ΩR7 = 1 Ω

+

R

R

R

R R

1

b

4

6 a

E

A

B C'

D

R R Ra = + =5 7 4Ω

R R R

R Rb =

+=

2 3

2 3

40Ω

+

R

R

R

R

1

b

4

c

E

A

B

R R R

R Rc

a

a

====++++

==== ====6

6

12

71 714Ω Ω.

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Electrical Basics Course Prof. Aldo Canova

Exercise 5: One source generator circuit

E = 48 VR1 = 1 Ω

R2 = 80 ΩR3 = 80 ΩR4 = 4 ΩR5 = 3 ΩR6 = 3 ΩR7 = 1 Ω

+

R

R

R1

b

d

E

A

B

R R Rd c==== ++++ ==== ++++ ==== ====4 4 127

407

5 714Ω Ω.

R

+

R e

E

A

B

R R R

R Re

b d

b d

====++++

==== ====1600 7

320 75Ω

+

Rf

E

I R R R f e= + = + =1 5 1 6Ω

I E R A f = = =48 6 8

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Electrical Basics Course Prof. Aldo Canova

Exercise 5: One source generator circuit

E = 48 VR1 = 1 Ω

R2 = 80 ΩR3 = 80 ΩR4 = 4 ΩR5 = 3 ΩR6 = 3 ΩR7 = 1 Ω+

R1

Re

E

A

B

I

V

+

AB

V R I E R

R RV AB e

e

e

= =+

=

1

40

R R1 dA

+

Rb

E

B

V

+

AB

II1 2

AB b AB d 1 2= = = =

I I R

R R A I I I Ad

b d

1 2 11 7====++++

==== ==== −−−− ====

Or

+

R

R

R

R

1

b

4

c

E

A

B

V

+

DC'

D

C'

I2

V R I V R

R RV V DC c AB

c

c

DC ' ==== ====++++

==== ====2

4

12

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Electrical Basics Course Prof. Aldo Canova

Exercise 5: One source generator circuit

E = 48 VR1 = 1 Ω

R2 = 80 ΩR3 = 80 ΩR4 = 4 ΩR5 = 3 ΩR6 = 3 ΩR7 = 1 Ω

+

R

R

R R

1

b

4

6 a

E

A

B C'

D

V

+

DC'

I 4I 3I 2

I V

R A I

V

R A DC DC

a

3

6

44 3==== ==== ==== ====' '

I I R

R R Aa

a

3 2

6

4====++++

====

Or

I I I A4 2 3 3==== −−−− ====

+

R

R

R

R R R

R1

2 3

4 5

6 7

E

A

B C

D

I4I

3I5

I6

I2

I

I7

I V

R A AB

5

2

0 5==== ==== . I V

R

V

R A AC AB

6

3 3

0 5==== ==== ==== .

I I I I I I 7 5 7 5 7 5++++ ==== ⇒⇒⇒⇒ ==== −−−− ==== .