Esercitazione 2 canova elt
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7/25/2019 Esercitazione 2 canova elt
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Electrical Basics Course Prof. Aldo Canova
Electrical Basic Course
Exercise 2
1) Equivalent resistance2) One source generator resistive network
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Electrical Basics Course Prof. Aldo Canova
Exercise 1
AR1 R2
R
R1=3 [Ω]R2=7.5 [Ω]
=
B
3
R5R6
R4=10 [Ω]R5=5 [Ω]R6=3 [Ω]
RAB?
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Electrical Basics Course Prof. Aldo Canova
A
R1
R3
R2//4
A
R1 R2//4
BR56
R R R
R R2 4
2 4
2 4
7 5 10
7 5 10 4 28 / /
.
. .=+
=
⋅
+= Ω
BR3+5R6
R R R3 5 3 5 8 5 13+ = + = + = Ω
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Electrical Basics Course Prof. Aldo Canova
A
B
R1 R(2//4)//(3+5)
R6
( ) ( ) [ ]Ω=+
⋅=
+=
+
+
+ 22.3
1328.4
1328.4
534 // 2
534 // 2
53 // 4 // 2 R R
R R R
( ) ( ) [ ]Ω=++=++= + 22.9322.33653 // 4 // 21 R R R R AB
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Electrical Basics Course Prof. Aldo Canova
R7
t2
Exercise 2 Calculate RAB:a) t1 open and t2 openb) t1 open and t2 closedc) t1 closed e t2 opend) t1 closed e t2 closed
R1=10 [Ω]R2=7.5 [Ω]R3=15 Ω
A
B
1
R2
4
R3
R5R6
t1
R4=18 [Ω]R5=3 [Ω]R6=8 [Ω]R7=10 [Ω]
Resultsa) RAB=13.16 [Ω]b) RAB=11.52 [Ω]c) RAB=12.81 [Ω ]d) RAB=10 [Ω]
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Electrical Basics Course Prof. Aldo Canova
A
R2R1
Calculate RAB:a) t1 open and t2 openb) t1 open and t2 closedc) t1 closed e t2 opend) t1 closed e t2 closed
R1=8 [Ω]R2=13 [Ω]R3=18 Ω
Exercise 3
B
R5 R4 t1
R3
t2
R4=6 [Ω]R5=10 [Ω]
Resultsa) RAB=15.49 [Ω]b) RAB=5.98 [Ω]c) RAB=14.95 [Ω ]d) RAB=4.95 [Ω]
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Electrical Basics Course Prof. Aldo Canova
t2
Exercise 4 Calculate RAB:a) t1 open and t2 openb) t1 open and t2 closedc) t1 closed e t2 opend) t1 closed e t2 closed
R1=10 [Ω]
A B1 2 3
t1
=R3=8 [Ω]
Resultsa) RAB=33 [Ω]b) RAB=10 [Ω]c) RAB=8 [Ω ]d) RAB=3.42 [Ω]
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Electrical Basics Course Prof. Aldo Canova
Exercise 5: One source generator circuit
+
R R R1 4 5
E
A D
E = 48 VR1 = 1 ΩR2 = 80 ΩR3 = 80 ΩR4 = 4 Ω
Evaluate all the current by using voltage and current divider
R2 3 6 7
B C
R5 = 3Ω
R6 = 3 ΩR7 = 1 Ω
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Electrical Basics Course Prof. Aldo Canova
Exercise 5: One source generator circuit
E = 48 VR1 = 1 Ω
R2 = 80 ΩR3 = 80 ΩR4 = 4 ΩR5 = 3 ΩR6 = 3 ΩR7 = 1 Ω
+
R
R
R
R R
1
b
4
6 a
E
A
B C'
D
R R Ra = + =5 7 4Ω
R R R
R Rb =
+=
2 3
2 3
40Ω
+
R
R
R
R
1
b
4
c
E
A
B
R R R
R Rc
a
a
====++++
==== ====6
6
12
71 714Ω Ω.
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Electrical Basics Course Prof. Aldo Canova
Exercise 5: One source generator circuit
E = 48 VR1 = 1 Ω
R2 = 80 ΩR3 = 80 ΩR4 = 4 ΩR5 = 3 ΩR6 = 3 ΩR7 = 1 Ω
+
R
R
R1
b
d
E
A
B
R R Rd c==== ++++ ==== ++++ ==== ====4 4 127
407
5 714Ω Ω.
R
+
R e
E
A
B
R R R
R Re
b d
b d
====++++
==== ====1600 7
320 75Ω
+
Rf
E
I R R R f e= + = + =1 5 1 6Ω
I E R A f = = =48 6 8
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Electrical Basics Course Prof. Aldo Canova
Exercise 5: One source generator circuit
E = 48 VR1 = 1 Ω
R2 = 80 ΩR3 = 80 ΩR4 = 4 ΩR5 = 3 ΩR6 = 3 ΩR7 = 1 Ω+
R1
Re
E
A
B
I
V
+
AB
V R I E R
R RV AB e
e
e
= =+
=
1
40
R R1 dA
+
Rb
E
B
V
+
AB
II1 2
AB b AB d 1 2= = = =
I I R
R R A I I I Ad
b d
1 2 11 7====++++
==== ==== −−−− ====
Or
+
R
R
R
R
1
b
4
c
E
A
B
V
+
DC'
D
C'
I2
V R I V R
R RV V DC c AB
c
c
DC ' ==== ====++++
==== ====2
4
12
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Electrical Basics Course Prof. Aldo Canova
Exercise 5: One source generator circuit
E = 48 VR1 = 1 Ω
R2 = 80 ΩR3 = 80 ΩR4 = 4 ΩR5 = 3 ΩR6 = 3 ΩR7 = 1 Ω
+
R
R
R R
1
b
4
6 a
E
A
B C'
D
V
+
DC'
I 4I 3I 2
I V
R A I
V
R A DC DC
a
3
6
44 3==== ==== ==== ====' '
I I R
R R Aa
a
3 2
6
4====++++
====
Or
I I I A4 2 3 3==== −−−− ====
+
R
R
R
R R R
R1
2 3
4 5
6 7
E
A
B C
D
I4I
3I5
I6
I2
I
I7
I V
R A AB
5
2
0 5==== ==== . I V
R
V
R A AC AB
6
3 3
0 5==== ==== ==== .
I I I I I I 7 5 7 5 7 5++++ ==== ⇒⇒⇒⇒ ==== −−−− ==== .