Report - Lezione 6 - unimi.it · Lezione 6- A. Andreazza - a.a. 2014/15 3 = + ψγµψ=ψ R γ µψ R +ψ L γ µψ L ψ R/L = 1 2 (1±γ 5)ψ J R µ=u(k!)γµ1 2 (1+γ 5)u(k) ⇒Lµν=2(kµk!ν+kνk!µ−(k⋅k")gµν)+2iεαµβνk

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