(eBook) - Fisica Teorica

download (eBook) - Fisica Teorica

of 214

Transcript of (eBook) - Fisica Teorica

  • 8/14/2019 (eBook) - Fisica Teorica

    1/214

  • 8/14/2019 (eBook) - Fisica Teorica

    2/214

  • 8/14/2019 (eBook) - Fisica Teorica

    3/214

    a

    xk

    xk

    S

    vc

  • 8/14/2019 (eBook) - Fisica Teorica

    4/214

    L2

    (

    p) = ( + 1) (

    p)

  • 8/14/2019 (eBook) - Fisica Teorica

    5/214

    ()

    ()

    S

    S

    HI

    A A

    e e

  • 8/14/2019 (eBook) - Fisica Teorica

    6/214

    m = 0

    C

    P

    T

    W

    W

  • 8/14/2019 (eBook) - Fisica Teorica

    7/214

  • 8/14/2019 (eBook) - Fisica Teorica

    8/214

  • 8/14/2019 (eBook) - Fisica Teorica

    9/214

    i

    t=

    2

    2m2

    E

    p

    E =p2

    2 m

    E

    p

    E E = i t

    ,

    p p = i .

    t+ = 0 ,

    (t, x) =

    |(t, x)

    |2 ,

    (t, x) = i2 m

    .

    V

    t

    V

    dV =

    V

    tdV =

    V

    dV =

    S

    nS dS ,

  • 8/14/2019 (eBook) - Fisica Teorica

    10/214

    S

    V

    nS S

    S

    S

    nS dS = 0

    t dV = 0 ,

    E2 = p2c2 + m2c4

    = c = 1

    pp = m2 ,

    p p = i

    = m2 .

    p

    p

    = (E,p)

    /x

    + m2 + m2

    + m2

    = 0

    p(x) = eipx

    eipx

    ,

    i

    tp(x) = p0 p(x) =

    p2 + m2 p(x) .

  • 8/14/2019 (eBook) - Fisica Teorica

    11/214

    j = 0 ,

    j =i

    2 m[ () () ] .

    j0

    j0 =i

    2 m

    t

    t

    (x) = 1, 2, . . . , N

  • 8/14/2019 (eBook) - Fisica Teorica

    12/214

    =N

    =1

    (x) =

    1(x)

    N(x)

    .

    =

    i m = 0 .

    iN

    n=1

    ()n(n) m = 0 ( = 1, . . . , N ) ,

    i + m .

    0 = (i + m) (i m)

    =

    1

    2( + ) + m

    2

    .

    + = 2 g .

  • 8/14/2019 (eBook) - Fisica Teorica

    13/214

    02

    =

    ,

    k2

    =

    (k = 1, 2, 3) .

    m

    i m = 0 , 0

    0

    i

    0 () +

    0

    m

    0 0

    = 0 .

    0

    0

    = 0 .

    0

    0 = 0

    =

    0

    .

    j

    j = 0 .

    j0 = ,

    (0)2 =

    = 00 ,

    k

    k

    = k .

    j

    j = ,

    0

    i

    + m = 0 ,

    0

    (0)2 =

  • 8/14/2019 (eBook) - Fisica Teorica

    14/214

    [] = 0 .

    k

    0

    k

    k

    =

    00k

    =

    0k0

    =

    00k

    =

    k

    k

    = 0 .

    N

    0k = k0 = (

    ) k0 .

    0

    k = (1)N

    k

    0 .

    0 = 0

    k = 0

    0

    k

    1 = (1)N = N

    .

    N = 4

    N = 2

    0

    k

    0

    1

    k

    i

    5

    5 i 0 1 2 3

    5 5 = 5

    5,

    = 0

    52

    =

    5

    = 5

    5

  • 8/14/2019 (eBook) - Fisica Teorica

    15/214

    a

    a

    a = 1, 2, . . . , 16

    1

    2 5 6 11 i

    2[, ]

    12 15 5

    16 5

    a

    1

    i

    a

    b

    a=b

    c =

    a b = c = 1, i .

    a = b

    a b

    c =

    a

    (a)2 =

    a =

    b

    ab = ba .

    a

    a > 1

    [a] = 0

    a > 1 .

    b a

    [a] =

    a

    b2

    =

    bab

    =

    b2

    a

    =

    [a] .

    a b

    = 0

    a=b .

  • 8/14/2019 (eBook) - Fisica Teorica

    16/214

  • 8/14/2019 (eBook) - Fisica Teorica

    17/214

    0 0 =

    0 0 = ,

    S

    4

    a

    a = a ,

    = S a = Sa S1

    i

    t= H

    H = i + m .

    k

    k = 0 k

    0

    = 0

    k

    = ,

    k

    = k ,

    k

    i j + j i = 2 ij ,

    i + i = 0 ,

    2 =

    .

    k k xk

    .

  • 8/14/2019 (eBook) - Fisica Teorica

    18/214

    0

    0 =

    00

    , k =

    0 kk 0

    , 5 =

    0

    0

    ,

    =

    00

    , k =

    0 k

    k 0

    .

    k

    1 =

    0 11 0

    , 2 =

    0 ii 0

    , 3 =

    1 00

    1

    .

    x x = x

    (i m) (x) = 0 , (i

    m)

    (x

    ) = 0 .

    x

    = x , x = x

    ,

    =

    , =

    .

    (x)

    (x)

    (x) = S(x) ,

    i m S (x) = 0 .

    S1 i S1 S m

    (x) = 0 .

  • 8/14/2019 (eBook) - Fisica Teorica

    19/214

    S1 S = .

    = g ,

    S1 S = .

    S =

    +

    =

    +

    =

    ( + )

    = 2 g

    = 2 g

    .

    =

    S

    = g +

    ,

    |

    | 1 .

    = .

    S = + a O ,

    O 4 4 O a

    S1 = a O ,

    a O

    + a O

    =

    g +

    .

    + a [ , O] = + .

  • 8/14/2019 (eBook) - Fisica Teorica

    20/214

    a [, O] = .

    O = a = i/4

    [,

    ]

    = g i = i g ,

    [A,BC] = {A, B} C B {A, C}

    [, ] = i [, g ] = i [, ] = i {, } i {, }

    = 2 i

    g g

    ,

    i4

    [, ] =

    .

    S = i4

    .

    S = e i4 .

    xk

    x1

    (R1)

    () =

    1 0 0 00 1 0 00 0 cos sin 0 0 sin cos

    =

    1 0 0 00 1 0 00 0 1 0 0 1

    + O(2)

    = g + 0 0 0 0

    0 0 0 00 0 0 10 0 1 0

    + O(2) = g + (r1) + O(2) ,

    (r1)

    =d(R1)

    ()

    d

    =0

    =

    0 0 0 00 0 0 00 0 0 10 0 1 0

  • 8/14/2019 (eBook) - Fisica Teorica

    21/214

    x1

    (r1)

    (r1)23 = +1 (r1)

    32 = 1 (r1)23 = 1 (r1)32 = +1

    (r1) = 23 + 32 = 2 23 ,

    = 223 x1

    SR1() = ei2

    23 .

    k

    ijk

    123 = +1

    ij = ijk k k = 12

    kij ij

    23 = 1

    SR1() = ei2

    1 .

    xk

    SRk() = ei2

    k =

    cos

    2+ i k sin

    2.

    ei

    2 k

    =

    n=0

    i2 kn

    n! =

    n=0

    i2 k2n

    (2n)! +

    n=0

    i2 k2n+1

    (2n + 1)!

    =

    n=0

    (1)n12

    2n

    (2n)!+ i k

    n=0

    (1)n12

    2n+1

    (2n + 1)!

    =

    cos

    2+ i k sin

    2,

    k

    2n

    =

    ,

    k

    2n+1

    = k , i2n = (1)n ,

    cos x =

    n=0

    (1)n x2n(2n)!

    , sin x =

    n=0

    (1)n x2n+1(2n + 1)!

    .

    SRk( + 2) = SRk() ,

    SRk

    k

    k = 0k5

  • 8/14/2019 (eBook) - Fisica Teorica

    22/214

    xk

    v

    x1

    x

    0= cosh x0

    sinh x1 ,

    x1 = sinh x0 + cosh x1 ,x

    2= x2 ,

    x3

    = x3 ,

    cosh = 1 v21/2 ,sinh = v .

    x1

    (1)

    () =

    cosh sinh 0 0 sinh cosh 0 0

    0 0 1 00 0 0 1

    =

    1 0 0 1 0 0

    0 0 1 00 0 0 1

    + O(2)

    = g +

    0 1 0 01 0 0 00 0 0 00 0 0 0

    + O(2) = g + (1) + O(2) ,

    (1)

    =d(1)

    ()

    d

    =0

    =

    0 1 0 01 0 0 00 0 0 00 0 0 0

    x1

    (1)

    (1)01 = 1 (1)10 = 1 (1)01 = 1 (1)10 = +1

    (1) = 01 + 10 = 2 01 ,

    = 201

    x1

    S1() = ei2

    01 .

    0k i2

    0, k

    = i 0 k = i k ,

    xk

    Sk() = e12

    k

    =

    cosh

    2

    k sinh

    2

    .

  • 8/14/2019 (eBook) - Fisica Teorica

    23/214

    S

    S

    S = ei4

    .

    0 0 =

    00 = i

    20

    ,

    0 = i2

    [, ] = ,

    0 S 0 = ei4

    ,

    0 S 0 = S1 .

    xk

    SRk() = ei

    2

    k

    .

    k

    SRk() = ei2

    k

    = ei2

    k

    = S1Rk ()

    SRk() k 0 = 0 k

    xk

    Sk() = e 12 k .

    k

    Sk() = e12

    k

    = e12

    k

    = Sk()

    Sk() k 0 = 0 k

  • 8/14/2019 (eBook) - Fisica Teorica

    24/214

    xP

    x = (x0,

    x)

    (x)P (x) = SP (x)

    i 0

    t+ i m

    (x) = 0

    i 0 t i mSP (x) = 0 .

    S1P i S1P 0 SP

    t i S1P SP m

    (x) = 0 .

    S1P 0 SP = 0

    S1P

    SP =

    = SP = P 0 ,

    P

    (t, x) (t, x) = (t, x) (t, x) = P (t, x) 0 P 0 (t, x)

    = |P|2 (t, x) (t, x)

    |P|2 = 1 P = ei P

    1/2

    P

    P = +1 SP

    = P =

    1 0 0 00 1 0 00 0 1 00 0 0 1

    .

  • 8/14/2019 (eBook) - Fisica Teorica

    25/214

    xT x = (x0, x)

    (x)T (x) = B (x) ,

    B

    B

    i 0

    t+ i m

    (x) = 0

    i 0

    t+ i m

    B (x) = 0 .

    i t

    B 0 + i B m B = 0 .

    B1

    i tB 0 B1+ i B B1 m = 0 .

    i

    t0 + i + m = 0 ,

    B0 B1 = 0 ,

    B B1 = .

    0 5

    0

    0 51

    = 0 ,

    0 5

    0 51

    = ,

    B

  • 8/14/2019 (eBook) - Fisica Teorica

    26/214

    C

    C C1 = ,

    B = T 0 5 C ,

    T C

    (x) a (x) ,

    a =

    , , , 5 , 5 ,

    (x) =

    S (x)

    (x) (x) 0 = (x) S 0 = (x) 0 S 0 .

    0 S 0 = S1 ,

    (x) = (x) S1 ,

    (x) = B (x) 0 = B 0 (x) 0 = (x) 0 B 0 .

    B

    0 B 0 = B1

    (x) = (x) B1 .

  • 8/14/2019 (eBook) - Fisica Teorica

    27/214

    a =

    (x) (x) = (x) S1 S (x) = (x) (x) .

    a =

    (x) (x) = (x) S1 S (x) = (x) (x) .

    a =

    (x) (x) = (x) S1 S (x) = (x) (x) .

    a = 5

    (x) 5 (x) = (x) S1 5 S (x) = (x)

    S1 5 S

    (x) .

    S = e i4 5,

    = 0

    = S1 5 S = 5 .

    SP = 00, 5

    = 0

    = S1P 5 SP = 5 .

    (x)5(x)

    (x) 5 (x) = (x) 5 (x) ,

    (x) 5 (x) = (x) 5 (x) = (x) 0 5 (x)

    = 0 ,

    + (x) k 5 (x)

    = k .

  • 8/14/2019 (eBook) - Fisica Teorica

    28/214

    a = 5

    (x) 5 (x) = (x) S1 5 S (x) .

    (x) 5 (x) = (x) 5 (x) ,

    (x) 5 (x) = (x) 5 (x) .

    5

  • 8/14/2019 (eBook) - Fisica Teorica

    29/214

    (i m) (x) = 0

    p p0 > 0

    p(x)

    ei px ei p x

    u(p)

    p,+(x) = ei px u(p)

    p0 > 0 .

    u(p)

    p,+(x) x

    p,+(x) = i p p,+(x) ,

    (p m) u(p) = 0 ,

    ( p m) u(p) = 0 .

    u(p) (

    p m) = 0 .

    v v v

  • 8/14/2019 (eBook) - Fisica Teorica

    30/214

    m=0

    p = (m,0) 0

    u(0) = 0 .

    u(0) =+(0)

    +(0)

    0

    0 =

    00

    ,

    0 00 +(0)+(0) = 0 .

    (1)+ (0) =

    10

    (2)+ (0) =

    01

    ,

    +(0) =

    00

    ,

    u(1)(0) =

    1000

    u

    (2)(0) =

    0100

    .

    u(r)(0) (r = 1, 2)

    i

    t p,(x) = |p0| p,(x) .

    p,(x) = ei px v(p)

    p0 > 0 .

    (

    p + m) v(p) = 0 .

  • 8/14/2019 (eBook) - Fisica Teorica

    31/214

  • 8/14/2019 (eBook) - Fisica Teorica

    32/214

    (

    p m) (

    p + m) u(r)(0)

    = 0 ,

    r = 1, 2 .

    u(r)(p) = C( p + m) u(r)(0) ,

    C

    u(r)(p) = C(

    p + m) u(r)(0)

    = C

    00

    E

    0

    0

    p +

    00

    m

    (r)+ (0)

    0

    = C

    E+ m p

    p E+ m

    (r)+ (0)

    0

    = C(E+ m) (r)+ (0) p (r)+ (0)

    = C(E+ m)

    (r)+ (0) pE+ m

    (r)+ (0)

    .

    C

    u(r)(p) u(s)(p) = rs .

    u(r)(p) u(s)(p) = |C|2 (E+ m)2

    (r)+ (0)

    (r)+ (0) p

    E+ m

    (s)+ (0) pE+ m

    (s)+ (0)

    = |C|2 (E+ m)2

    1 p

    2

    (E+ m)2

    rs

    = |C|2 2 m (E+ m) rs ,

    C =12 m (E+ m) ,

    u(r)(p) =

    p + m2 m (E+ m)

    u(r)(0) ,

    u(r)(p) = u(r)(0)

    p + m2 m (E+ m)

    .

  • 8/14/2019 (eBook) - Fisica Teorica

    33/214

    u(r)(p)

    u(r)(p)

    u(r)(p)

    u(r)(p) (r)+ (p)(r)+ (p)

    =E+ m

    2 m

    (r)+ (0) pE+ m

    (r)+ (0)

    .

    u(1)(p) =

    E+ m

    2 m

    10

    p

    E+ m

    10

    ,

    u(2)(p) =E+ m

    2 m

    01

    pE+ m

    01

    .

    v(r)(p) = C(

    p + m) v(r)(0) .

    v(r)(p) = C(

    p + m) u(r)(0)

    = C 0

    0

    E+

    0 0

    p + 00

    m 0

    (r) (0)

    = C(E+ m)

    pE+ m (r) (0)(r) (0)

    .

    v(r)(p) v(s)(p) =

    |C

    |2 (E+ m)2

    (r) (0)

    p

    E+ m (r) (0)

    p

    E+ m(s) (0)

    (s) (0)

    = |C|2 (E+ m)2

    p2

    (E+ m)2 1

    rs

    = |C|2 2 m (E+ m) rs .

    v(r)(p) v(s)(p) = rs ,

  • 8/14/2019 (eBook) - Fisica Teorica

    34/214

    C

    v(r)(p) =

    p + m

    2 m (E+ m)

    v(r)(0) ,

    v(r)(p) = v(r)(0) p + m2 m (E+ m)

    .

    v(r)(p)

    v(r)(p)

    (r) (p)

    (r) (p)

    =

    E+ m

    2 m

    pE+ m (r) (0)(r) (0)

    .

    v(1)(p) =

    E+ m

    2 m

    p

    E+ m

    10

    10

    ,

    v(2)(p) =

    E+ m

    2 m

    p

    E+ m

    01

    01

    .

    u(r)(p) v(s)(p) = 0 ,

    v(r)(p) u(s)(p) = 0 .

    uu uu

    pu = mu

    u(r)(p) u(s)(p) = u(r)(p) 0 u(s)(p) = u(r)(p)

    p 0 + 0

    p

    2 mu(s)(p)

    = u(r)(p)g0p

    mu(s)(p) =

    E

    mu(r)(p) u(s)(p) =

    E

    mrs .

    p,+(x) p,+(x) d3x

    d3x =1 v2/c2 d3x

    = p,+(x) p,+(x) = u(p) u(p)

    = /

    1 v2/c2 = E/m

  • 8/14/2019 (eBook) - Fisica Teorica

    35/214

  • 8/14/2019 (eBook) - Fisica Teorica

    36/214

    V

    d3x (r)

    p,+

    (x)

    (s)p,+(x) = |N|2 u(r)

    (p) u(s)(p) p,p

    V

    d3x = |N|2 Em

    V rs p,p ,

    N =1V

    m

    E.

    d3x (r)p,+

    (x) (s)p,+(x) = |N|2 u(r)

    (p) u(s)(p)

    d3x ei(pp

    )x = |N|2 Em

    rs (2 )3 3(p p) ,

    N =1

    (2 )3/2

    mE

    .

    (r)p,(x) =1V

    m

    Eei px v(r)(p)

    (r)p,(x) = 1(2 )3/2

    mE

    ei px v(r)(p)

    (r)p,+(x) (r)

    p,(x) d3x

    (r)p,+

    (x)

    (s)p,(x) = 0 .

    u(r)(p) = u(r)(0) p + m2 m (E+ m) ,

    v(r)(p) = v(r)(0) p + m

    2 m (E+ m),

    p = (p0,p) = (p0, p)

    u(r)(p) v(s)(p) = 0 ,

    v(r)(

    p) u(s)(p) = 0 .

  • 8/14/2019 (eBook) - Fisica Teorica

    37/214

    (r)

    p,+(x) (r)

    p,(x)

    (x) = r

    d3p b(r)p (r)p,+(x) + d(r)p (r)p,(x)=

    1

    (2)3/2

    r

    d3p

    m

    E

    b(r)p u

    (r)(p) eipx + d(r)p

    v(r)(p) eipx

    .

    b(r)p d

    (r)p

    1

    (2)3/2

    d3p 1

    V

    p

    .

    (x)

    d3x (x) (x) = 1 ,

    r

    d3p

    |b(r)p |2 + |d(r)p |2

    = 1 .

  • 8/14/2019 (eBook) - Fisica Teorica

    38/214

    +(p)

    r=1,2

    u(r)(p) u(r)(p) ,

    (+(p))

    r=1,2

    u(r) (p) u(r) (p) .

    +(p)

    (+(p)) u(s) (p) =

    r=1,2

    u(r) (p)

    u(r) (p) u

    (s) (p) = u

    (s) (p)

    +(p) v(s)(p) = 0 .

    +(p)

    (+(p))2 = +(p)

    r=1,2

    u(r) (p) u(r) (p)

    s=1,2

    u(s) (p) u(s) (p) =

    r,s

    u(r) (p)

    u(r) (p) u

    (s) (p)

    rs

    u(s) (p)

    =

    r=1,2

    u(r) (p) u(r) (p) .

    (p) r=1,2

    v(r)

    (p) v(r)

    (p) ,

    ((p)) v(s) (p) = v

    (s) (p) ,

    (p) u(s)(p) = 0 ,

    ((p))2 = (p) .

  • 8/14/2019 (eBook) - Fisica Teorica

    39/214

    +(p)

    +(p) =1

    2 m (E+ m)(

    p + m)

    r=1,2

    u(r)(0) u(r)(0)

    +(0)(

    p + m) ,

    +(0)

    0

    +(0) = 0 ,

    +(0)

    0

    = 0 .

    (+(0))2 = +(0)

    +(0) =1 + 0

    2.

    +(0) =1+0

    2+ B

    B = 0

    +(p) =1

    2 m (E+ m)(

    p + m)1 + 0

    2(

    p + m) .

    (

    p + m) 0 (

    p + m) = (

    p + m)

    0p0 kpk + m

    0

    = (p + m)

    p + m + 2 0p0

    0

    = 2 E(

    p + m) ,

    (

    p + m) (

    p + m) = (

    p + m) (

    p m + 2 m)= 2 m (

    p + m) ,

    (p + m)

    1 + 0

    2(

    p + m) = (E+ m) ( p + m) ,

    +(p) =

    p + m

    2 m.

    +(p)

    (+(p)) =

    p + m

    2 m= 0

    p + m

    2 m0 = 0 +(p)

    0 .

  • 8/14/2019 (eBook) - Fisica Teorica

    40/214

    (p)

    (p) =

    p + m

    2 m.

    (p)

    ((p)) = 0 (p)

    0 .

    +(p) + (p) = ,

    +(p) (p) = (p) +(p) = 0 .

  • 8/14/2019 (eBook) - Fisica Teorica

    41/214

  • 8/14/2019 (eBook) - Fisica Teorica

    42/214

    (x)

    (x) =

    1 + i J3

    (x) ,

    J = L +1

    2 .

    L

    /2

    /2

    /2

    J = L +1

    2 .

    3

    =

    00

    3 u(r)(m,0) = 3 00 3

    (r)+ (0)0

    = 3 (r)+ (0)0

    = (1)+ (0)

    0 ,(2)+ (0)

    0

    .

    3 v(r)(m,0) =

    3 00 3

    0

    (r) (0)

    =

    0

    3 (r) (0)

    =

    0

    (1) (0)

    ,

    0

    (2) (0)

    .

    3 u(1)(m,0) = +u(1)(m,0)

    3 u(2)(m,0) = u(2)(m,0)

    3 v(1)(m,0) = +v(1)(m,0)

    3 v(2)(m,0) = v(2)(m,0)

    u(r)(m,0)

    v(r)(m,0)

    r = 1, 2

    i/t

    3

    p0 1/2

  • 8/14/2019 (eBook) - Fisica Teorica

    43/214

    j , k = 2 i

    jk ,

    j=k

    j , k

    =

    0 j 5 , 0 k 5

    = j , k = 2 j k .

    j

    j =1

    2jmn mn =

    i

    2jmn m n ,

    jk j

    jk j =i

    2

    jk jmn m n =i

    2 km n

    kn m

    m n =i

    2 k

    k = i

    k ,

    j k = i jk

    (H)

    d(H)

    dt= i

    H , (H)

    +

    (H)

    t.

    (H)

    (S)

    (H)(t) = eiH t (S) eiH t .

    H = p + m .

    L

    Lj

    dLj

    dt= i

    H , Lj

    = i

    p , Lj = i k pk , Lj

    = jk kp = ( p)j ,

  • 8/14/2019 (eBook) - Fisica Teorica

    44/214

    dL

    dt= p .

    L

    /2

    j

    dj

    dt= i

    p + m , j = i p , j ,

    ,

    = 0

    [ p , j]

    = 5

    i kpk , j = i pk k 5 , j = i pk k , j 5 = 2pk kj 5= 2 kjpk = 2 ( p)j .

    d

    dt= 2 p

    p

    [H , p] = 0

    d

    dt p = i H , p = i H , p .

    H ,

    = 2 i p

    d

    dt

    p

    = 0 .

    s p|p|

    J

    dJ

    dt=

    d

    dt

    L +

    1

    2

    = 0 ,

    J

  • 8/14/2019 (eBook) - Fisica Teorica

    45/214

    E

    B

    A

    E = A

    t A0 ,

    B = A .

    F

    F A A ,

    F =

    0 E1 E2 E3E1 0 B3 B2E2 B3 0 B1E3

    B2 B1 0

    .

    A

    E

    B

    F

    F

    A(x) A(x) + (x) .

    A(x)

  • 8/14/2019 (eBook) - Fisica Teorica

    46/214

    E = , B

    E

    t= j ,

    = F = j ,

    B = 0 , E+

    B

    t= 0 ,

    = F + F + F = 0 .

    =e2

    4c=

    e2

    4

    .

    F

    j

    j = F

    = 0 .

    F A A

    A

    A (A) = j .

    p p ec

    A ,

    e

    p p ec

    A ,

    + i e A .

    i

    m

    i m i e A m

    (i

    e

    A m) (x) = 0 .

  • 8/14/2019 (eBook) - Fisica Teorica

    47/214

    (x)

    (x)

    (x)

    (x) = ei

    (x)

    (x)

    j =

    (x) (x) = ei(x) (x) .

    (x)

    ei(x) (x)

    = iei(x) (x) (x) + ei(x) (x) ,

    [i (x) m] (x) = 0 .

    A

    A (x) = (x)/e

    A A = A 1

    e(x) .

    (x)

    A(x)

    D

    D = + ieA .

    (x)

    ei(x) (x) ,

    A(x) A(x) 1e

    (x) ,

    D(x) ei(x) D(x) .

  • 8/14/2019 (eBook) - Fisica Teorica

    48/214

  • 8/14/2019 (eBook) - Fisica Teorica

    49/214

    p e A + m + e A0 = E

    (x) =

    (x)(x)

    ,

    0 0 p e

    A(x)(x) = E e A

    0

    00

    m

    00

    (x)(x) ,

    p e A

    (x) =

    E e A0 m(x) ,

    p e A

    (x) =

    E e A0 + m(x) . p e A

    (x) =1

    E

    e A0 + m

    p e A

    (x) 1

    E

    e A0 + m

    (x) .

    (x)

    1E e A0 + m (x) =

    E e A0 m(x) .

    v/c 1

    E m e A0 m .

    E(nr) E m m ,

    1

    E e A0 + m =1

    2 m + E(nr) e A0

    =1

    2 m

    1 E

    (nr) e A02 m

    + . . .

    .

  • 8/14/2019 (eBook) - Fisica Teorica

    50/214

  • 8/14/2019 (eBook) - Fisica Teorica

    51/214

    B ,

    e 2 m c

    2 e2 m c

    1

    2

    = g

    e

    2 m cs ,

    s =1

    2 ,

    ,

    g = 2 ,

    .

    B

    B |e| 2 m c

    = 0.579 1014 MeV gauss1 .

    B

    Hint

    g = 2

    g = 2

    g = 2

    1 +

    2

    .

    (x)

    p e A

    2 m(x) .

    A = 0

    1

    2m p

    1 E

    (nr) e A02 m

    p + e A0

    (x) = E(nr)(x) .

    v2/c2

    E(nr) e A0 mv2/2

    E(nr) e A0m c2

    = O

    v2

    c2

    .

  • 8/14/2019 (eBook) - Fisica Teorica

    52/214

    (v2/c2)2

    v2/c2

    =

    d3x = 1

    1 =

    d3x

    +

    d3x1 + p24 m2

    .

    A = 0

    (x) p2 m

    (x) = (x) vc

    (x) .

    v2/c2

    X = ,

    = 1 + p2

    8 m2.

    d3x XX =

    d3x

    1 +

    p2

    4 m2

    = 1 + O

    v2

    c2

    2.

    1 = 1X

    1

    1

    2m p

    1 E

    (nr) e A02 m

    p + e A0

    1X(x) = E(nr)2X(x) .

    1 1 p2

    8 m2,

    1 p

    2

    8 m2

    1

    2m p

    1 E

    (nr) e A02 m

    p + e A0

    1 p

    2

    8 m2

    X(x)

    = E(nr)

    1 p2

    4 m2

    X(x) ,

    1 p28 m2( p)22 m + e A01 p28 m2 p E(nr) e A04 m2 pX(x)= E(nr)

    1 p

    2

    4 m2

    X(x) ,

    p2

    2 m+ e A0 (p

    2)2

    8 m3

    p2

    8 m2, e A0

    p E

    (nr) e A04 m2

    p

    X(x)

    = E(nr)

    1 p2

    4 m2

    X(x) .

  • 8/14/2019 (eBook) - Fisica Teorica

    53/214

    E(nr)p2

    E(nr) , p2

    /2

    p2

    2 m+ e A0 (p

    2)2

    8 m3+

    1

    8 m2

    p2 , E(nr) e A0 2 p E(nr) e A0 pX(x)= E(nr) X(x) .

    {A2 , B} 2 A B A = [A , [A , B]] p2 , E(nr) e A0 2 p E(nr) e A0 p = p , p , E(nr) e A0

    = p , p , e A0 .

    p , e A0

    = i e E ,

    p , E = j k pj , Ek+ j , kEkpj=

    jk + i jk

    pj , Ek

    + 2 i jk Ekpj

    = p E+ i

    p E

    2 i

    Ep

    = i E 2 i

    Ep

    .

    p E

    p

    E =

    i

    E = i

    A0 = 0 .

    p2

    2 m+ e A0 (p

    2)2

    8 m3 c2 e

    4 m2 c2

    Ep

    e2

    8 m2 c2 E

    X(x) = E(nr) X(x) ,

    e A0

    p2

    2 m (p2)2

    8 m3 c2

    p2 c2 + m2 c4 m c2 = m c2

    1 +

    p2 c2

    m2 c4

    1/2 m c2

    m c2

    1 +p2

    2 m2 c2 (p

    2)2

    8 m4 c4

    m c2

    p2

    2 m (p

    2)2

    8 m3 c2.

  • 8/14/2019 (eBook) - Fisica Teorica

    54/214

    e4 m2 c2

    Ep

    B = E

    p

    m c

    =e

    2 m c ,

    E = rr

    dA0

    dr,

    Ep = 1r

    dA0

    dr (r p) = 2

    1r

    dA0

    dr1

    2 (r p)

    = 2

    1

    r

    dA0

    drs ,

    e4 m2 c2

    Ep

    =e

    2 m2 c21

    r

    dA0

    drs .

    e2

    8 m2 c2 E

    A0(r + r) = A0(r) + r A0 + 12

    xi xj2A0

    xi xj,

    A0(r + r)

    = A0(r) +1

    2

    2A0

    xi xj

    xi xj

    ,

    xi xj = 13 (r)2 ij 13 m c2

    ij ,

    (eA0) e 2

    6 m2 c2A0 = e

    2

    6 m2 c2 E .

  • 8/14/2019 (eBook) - Fisica Teorica

    55/214

  • 8/14/2019 (eBook) - Fisica Teorica

    56/214

    K

    K =

    L +1

    2

    1

    2

    =

    L +

    1

    2

    23 1

    2

    =

    L +

    .

    J

    K

    J , K

    = 0 .

    H

    J2

    J3

    K

    H = E ,J2

    = 2j (j + 1) ,J3 = j3 ,K = .

    K2

    J2

    K2

    K2 =

    L +

    L +

    =

    L +

    L +

    .

    a b = a b + i a b

    L

    L

    = L2

    + i

    L L

    iL

    = L2 L ,

    K2 = L2

    L + 2

    L + 2 = L

    2+

    L + 2 .

    J2

    =

    L +

    1

    2

    2= L

    2+ L + 3

    42 .

    K2 = J2

    +1

    42 .

  • 8/14/2019 (eBook) - Fisica Teorica

    57/214

    2 2 = 2j (j + 1) +

    1

    42 = 2

    j +

    1

    2

    2,

    =

    j +1

    2

    .

    K

    K =

    L +

    =

    00

    L + 00

    L +

    =

    L + 00 L

    .

    K =

    =

    ,

    L + 0

    0 L = ,

    L +

    = , L +

    = ,

    L = (1 + ) , L = (1 ) .

    J2

    L L2

    J2

    L2

    J2

    =

    L +

    1

    2

    2= L

    2+ L + 3

    42 ,

    L2

    = J2 L 3

    42 ,

  • 8/14/2019 (eBook) - Fisica Teorica

    58/214

    L2

    =

    J2 L 3

    42

    =

    2j (j + 1) + 2 (1 + ) 3

    42

    = 2 j (j + 1) + + 14

    2 ( + 1) ,

    L2

    =

    J2 L 3

    42

    =

    2j (j + 1) + 2 (1 ) 3

    42

    = 2j (j + 1) + 1

    4

    2 ( + 1) .

    L2

    j

    =

    L2

    ( + 1) = j (j + 1) + +

    14

    ,

    ( + 1) = j (j + 1) + 14 .

    = +j + 12 = = j + 12 , = j 12 ,

    =

    j +1

    2

    =

    = j 12 , = j +

    12

    ,

    c p + m c2 + V(r)(x) = E (x) ,

    (x) =

    (x)(x)

    ,

  • 8/14/2019 (eBook) - Fisica Teorica

    59/214

    c p (x) = E V m c2(x) ,c p (x) =

    E V + m c2

    (x) .

    (x) (x) = g(r) Yjj3 , = i f(r) Yjj3 ,

    Yjj3 J2

    J3

    L2

    S2

    Yjj3 = m,ms m s ms |j j3 Y,m s,ms .

    p

    p = rr2

    ( r) ( p) ,

    ( r) ( p) = r p + i (r p) = i r r

    + i L ,

    p =

    rr2 i r

    r

    + i

    L .

    p = i rr2

    r

    r+ L

    = i

    rr2

    r

    r (1 )

    = r

    rYjj3

    df

    dr+

    (1 )r

    f

    .

    r

    Yj

    j3

    J2

    J3

    L2

    2j(j + 1)

    j3 2( + 1)

    Yjj3 J2

    J3 L2

    J2

    J3 Yjj3

    r =

    rr

    Yjj3 = 1 Yjj3 ,

  • 8/14/2019 (eBook) - Fisica Teorica

    60/214

    1 Yjj3

    rr

    2= 1

    rr

    Yjj3 = 2 Yjj3 .

    12 = +1

    Yjj3 Yjj3

    1 = 2 = 1 r

    rYjj3 = Yjj3 ,

    rr

    Yjj3 = Yjj3 .

    p = dfdr + 1 r fYjj3 .

    p = i

    dg

    dr+

    1 +

    rg

    Yjj3 .

    c

    df

    dr+

    1 r

    f=

    E V m c2 g ,

    cdg

    dr+

    1 + r

    g

    =

    E V + m c2 f . f(r) g(r)

    V(r)

    F(r) = r f(r) , G(r) = r g(r) ,

    c

    dF

    dr

    rF

    = E V m c2G ,

    c

    dG

    dr+

    rG

    =

    E V + m c2F .

  • 8/14/2019 (eBook) - Fisica Teorica

    61/214

    V(r) = 14

    Z e2

    r.

    z1 =m c2 + E

    c, z2 =

    m c2 E c

    ,

    =Z e2

    4 c Z ,

    =

    z1 z2 r .

    z1 z2 =(m c2)

    2 E2( c)2

    0

    dF

    d

    F = z2

    z1

    G ,dG

    d+

    G =

    z1z2

    +

    F .

    dF

    d=

    z2z1

    G ,

    dG

    d = z1z2 F ,=

    d2F

    d2= F ,

    d2G

    d2 = G ,

    F() me , G() me ,

    m

    m

    F() me , G() me .

  • 8/14/2019 (eBook) - Fisica Teorica

    62/214

  • 8/14/2019 (eBook) - Fisica Teorica

    63/214

    bn =

    z1z2

    an .

    n an

    an1=

    2

    n,

    n

    an n e2 ( ) .

    n bn n e2 ( ) .

    n an

    n

    n bn

    n

    F()

    G()

    F() s e

    G() s e

    an+1

    an = 0 , an+1 = 0 .

    n = n + 1

    an = z2z1

    bn bn+1 ,

    (s + n + 1 + ) bn+1 bn =

    z1z2

    an .

    bn+1 = 0

    an =

    z2z1

    bn .

    n = n bn

    2

    z1 z2 (s + n) = (z1 z2) .

    z1 z2

    z1 z2 =

    1

    c

    (m c2)2 E ,

    z1 z2 = 2 E c

    ,

  • 8/14/2019 (eBook) - Fisica Teorica

    64/214

    n j n

    1

    1S1/2

    2

    2P3/2

    3 3D5/2

    1

    2S1/2

    +1

    2P1/2

    2

    3P3/2

    +2

    3D3/2

    1

    3S1/2

    +1

    3P1/2

    E2

    1 +2

    (s + n)2

    =

    m c22

    ,

    E = m c2

    1 + (Z )2

    n+

    (j+ 12)2(Z )2

    2.

    E

    n

    || = j + 1/2

    = (j + 1/2)

    = + (j + 1/2) = = j + 1/2 ,

    = (j + 1/2) = = j 1/2 .

    n = 0

    < 0

    n = 0

    (s + ) b0 = a0 ,

    a0 =

    z2z1

    b0 ,

    = s + =

    z2z1

    .

    s > 0

    < 0

  • 8/14/2019 (eBook) - Fisica Teorica

    65/214

    n

    j n

    n = n + || = n +

    j +1

    2.

    =

    2

    E = m c2

    1 12 (Z )2n2

    12

    (Z )4

    n3

    1

    j + 1/2 3

    4 n

    +O

    6 .

    0 E mc2

    4

    n

    j

    n

    j

    Z = 1

    E = m c21

    2

    4

    n3 1jmin + 1/2 1jmax + 1/2= m c2

    1

    2

    4

    n3jmax jmin

    (jmin + 1/2) (jmax + 1/2).

    E(2P) E2P3/2 E2P1/2 = 425

    m c2

    = 8.87 1011 m c2 = 4.53 105 eV ,

    (2P) = 12

    E

    = E2 6.58 1022 MeV sec = 11 GHz .

    V = Ze24r

  • 8/14/2019 (eBook) - Fisica Teorica

    66/214

  • 8/14/2019 (eBook) - Fisica Teorica

    67/214

    TE

    0

    m c2 eee

    eee

    eee

    eee

    eee

    eee

    eee

    eee

    eee

    eee

    eee

    eee

    + m c2

    Hhf = 23

    e p |n(0)|2 ,

    n(0) e

    p

    p = (1 + ap)|e|

    2 mp c

    p .

    mp ap = 1.79

    N

    N |e| 2 mp c

    = 3.15 1018 MeV gauss1 .

    n

    |n(0)|2 = 1 a30 n

    3, a0 =

    1

    m c

    Hhf =2

    3(1 + ap)

    1

    n3m

    mpm c2 4 e p .

    e p =

    1

    3

  • 8/14/2019 (eBook) - Fisica Teorica

    68/214

    Ehfn=1( ) =8

    3(1 + ap)

    m

    mpm c2 4

    = 5.88 106 eV ,

    =1

    2

    E

    =

    E

    2 6.58 1016 eV secGHz

    109 sec1= 1.42 GHz .

    m/mp

    n

    j

  • 8/14/2019 (eBook) - Fisica Teorica

    69/214

    mc2

    mc2 Eleg

    E(E> 0)

    E = Evuoto (E) = Evuoto + E,

    Evuoto

    Eoss = E

    Evuoto =

    E.

    Q = Qvuoto e = Qvuoto + |e| , Qoss = Q Qvuoto = |e| .

    E

    E

    e = |e|

  • 8/14/2019 (eBook) - Fisica Teorica

    70/214

    m c2e

    ee

    eee

    eee

    eee

    eee

    eee

    eee

    eee

    eee

    eee

    eee

    eee

    + m c2

    m

    T

    E1

    E2

    E1

    E2 E = E2 + E1

    E2 E1

    e + e+ .

    e + e+ . . . ,

    e + e+ 2 .

  • 8/14/2019 (eBook) - Fisica Teorica

    71/214

    e

    e+

    e+

    e

    e+

    e

    e+

    e

    p

    e

    S

    E(2P1/2)

    E(2S1/2) = 27MHz

    2S1/2

    2P1/2

    (i

    e

    A m) (x) = 0 .

    (i

    + e

    A m) c(x) = 0 .

    c(x)

    i e A m = 0 ,

  • 8/14/2019 (eBook) - Fisica Teorica

    72/214

  • 8/14/2019 (eBook) - Fisica Teorica

    73/214

    =

    0 =

    1 00 1

    001

    0

    eimt = eimt

    00

    10

    ,

    c = iceimt

    0 0 0 i0 0 i 00 i 0 0i 0 0 0

    00

    10

    = ceimt

    0100

    .

    c

    |e|

    (r)+ (x) = e

    imt

    (r)

    0

    ,

    (1) = 10 ,

    (2) =

    01

    ;

    (r) (x) = e

    +imt

    0

    (r)

    .

    P = 0 =

    (r)+ (x)

    P +(r)+ (x) ,(r) (x)

    P (r) (x) .

  • 8/14/2019 (eBook) - Fisica Teorica

    74/214

  • 8/14/2019 (eBook) - Fisica Teorica

    75/214

    (i

    m) (x) = e

    A(x) (x)

    (x) = 0(x) +

    d4x K(x x) e

    A(x) (x) ,

    0(x) K(x x)

    4 4

    (i

    m) K(x x) = 4(x x) .

    i

    m

    (x) = 0(x) + d4xK(x x)e A(x) 0(x) + d4xK(x x)e A(x) [0(x) + . . . ]= 0(x) +

    d4xK(x x)e A(x)0(x)

    +

    d4xd4xK(x x)e A(x)K(x x)e A(x)0(x) + . . . .

    K(x x)

  • 8/14/2019 (eBook) - Fisica Teorica

    76/214

    T

    ERep0

    Imp0

    r rE+E

    E E E ECF

    CF

    K(x

    x)

    K(xx)

    K(x x) = 1(2)4

    d4p K(p) eip(xx

    )

    (i

    m) K(x x) = 1(2)4

    d4p (

    p m) K(p) eip(xx) .

    4(x x) = 1(2)4

    d4p eip(xx

    ) .

    (

    p m) K(p) =

    ,

    K(p) =

    p + m

    p2

    m2

    ,

    (

    p + m) (

    p m) = p2 m2

    K(x x) = 1(2)4

    d4p

    p + m

    p2 m2 eip(xx) .

    K(p)

    p20 p2 m2 = 0 .

  • 8/14/2019 (eBook) - Fisica Teorica

    77/214

    p0

    p0 =

    p2 + m2 E .

    p0

    p0

    K(p)

    K(x x)

    CF

    p0

    C

    f(z) dz = 2 i

    n

    limzan

    (z an) f(z)

    ,

    z = an f(z) C

    eip0(x0x0) = ei (x0x

    0)Re(p0) e(x0x

    0)Im(p0)

    x0 > x0

    x0 < x0

    KF

    KF(x x) = 1(2)4

    CF

    d4p

    p + m

    p2 m2 eip(xx) ,

    KF(x

    x) =

    2i(x0

    x0)

    1

    (2)4 d

    3p lim

    p0E(p0 E)p + m

    (p0 E) (p0 + E)eip(xx

    )

    + 2i(x0 x0)

    1

    (2)4

    d3p lim

    p0E

    (p0 + E)

    p + m

    (p0 + E) (p0 E) eip(xx)

    = i

    d3p

    (2)32E

    (x0 x0) ( p + m) eip(xx

    ) (x0 x0) ( p m) eip(xx)

    p0=E.

    p0

  • 8/14/2019 (eBook) - Fisica Teorica

    78/214

    T

    ERep0

    Imp0

    x0 > x0

    s

    r rE+E

    E E E E

    T

    ERep0

    Imp0

    x0 < x0

    s

    r rE+E

    E E E E

    E E+ i +E +E i

    KF(x x) = 1(2)4

    d4p

    p + m

    p2 m2 + i eip(xx) ,

    (p0 + E i ) (p0 E+ i ) = p2 m2 + i .

    j(x)

    + m2(x) = j(x) .

    (x) = 0(x) +

    d4x G(x x)j(x) ,

    G(x x)

    + m2

    G(x x) = 4(x x) .

  • 8/14/2019 (eBook) - Fisica Teorica

    79/214

    G(x x) = 1(2)4

    d4p G(p) eip(xx

    ) ,

    + m2

    G(x x) = 1

    (2)4

    d4p

    p2 + m2G(p) eip(xx) .

    4(xx)

    G(p) = 1p2 m2 .

    GF(x) = 1(2)4

    d4p

    1

    p2 m2 + i eipx ,

    GF(x) KF(x)

    (i

    + m) GF(x) = 1(2)4

    d4p

    p + m

    p2 m2 + i eipx = KF(x) .

  • 8/14/2019 (eBook) - Fisica Teorica

    80/214

  • 8/14/2019 (eBook) - Fisica Teorica

    81/214

    c

    [

    ] = [E t] ,

    [c] =

    t1 .

    = c = 1 .

    [E] = t1

    = 1

    .

    E2 = p2 + m2

    [E] = [|p|] = [m] .

    c = 197

    ,

    197

    = 1 .

  • 8/14/2019 (eBook) - Fisica Teorica

    82/214

  • 8/14/2019 (eBook) - Fisica Teorica

    83/214

    v v =

    (v0

    , v1

    , v2

    , v3

    )

    v0

    v1

    v2

    v3

    v = (v1, v2, v3)

    v = (v0, v1, v2, v3) v

    v = g v ,

    g

    g

    g =

    1 0 0 00 1 0 00 0 1 00 0 0 1

    .

    v

    v0 = v0 , vk = vk (k = 1, 2, 3) .

    (g)

    g g = g ,

    g 1 0 0 0

    0 1 0 00 0 1 00 0 0 1

    .

    . . .

    k

    i

    j

    . . .

    u v = u0 v0 + u

    1 v1 + u2 v2 + u

    3 v3 .

  • 8/14/2019 (eBook) - Fisica Teorica

    84/214

    g = g =

    1 0 0 00 1 0 00 0 1 00 0 0 1

    .

    u

    v

    u v = u v = u v = g u v = g u v = u0 v0 u v .

    v2 v v

    v2 > 0

    v2 = 0

    v2 < 0

    L()

    v

    v

    v

    = v ,

    v2

    = v2 g v v = g v v .

    g

    = g .

    v = v ,

  • 8/14/2019 (eBook) - Fisica Teorica

    85/214

    Tr(1 . . . n) = Tr

    52

    1 . . . n

    = Tr

    5 1 . . . n 5

    = (1)nTr

    52

    1 . . . n

    = (1)nTr(1 . . . n) ,

    5

    k

    Tr() = 0 ,

    Tr

    5

    = 0 .

    n

    Tr( ) =1

    2Tr( + ) = g Tr(

    ) = 4 g .

    Tr( ) = g Tr( ) g Tr( ) + g Tr( )= 4 (g g g g + g g) .

    n

    n

    n 2 Tr(123 n) = g12Tr[34 n ] g13Tr[24 n ] +

    + g1nTr[23 n1 ] .

    Tr

    5

    = 0 ,

    Tr

    5

    = 0 .

  • 8/14/2019 (eBook) - Fisica Teorica

    86/214

    Tr

    ()2 5

    = Tr 5 = Tr()2 5

    ()2

    Tr(5) =

    Tr(5) = 0

    5

    Tr

    5

    = i Tr 0 1 2 3= i

    2Tr

    0 1 2 3 i

    2Tr

    0 1 2 3

    = i g3 Tr 0 1 2+ i g2 Tr 0 1 3 i g1 Tr 0 2 3+ i g0 Tr

    1 2 3

    i g Tr0 1 2 3= 0 .

    5

    5

    Tr

    5

    = 4 i ,

    0123 = +1

    Tr

    0 1 2 3 5

    = i Tr

    55

    = 4 i = 4 i 0123 .

    a

    1

    n

    Tr(1 2 n1 n) = Tr(n n1 2 1) .

    C1C =

    C

    CC1 =

    n

    Tr(1 2 n1 n) = TrC 1 C1 C 2 C1 C1C n1 C1 C n C1= (1)n Tr(

    1

    2

    n1

    n) = Tr

    [n n1 2 1 ]T

    = Tr(n n1

    2 1) .

  • 8/14/2019 (eBook) - Fisica Teorica

    87/214

    { , } = 2 g

    ,

    0 0 = .

    44

    S

    S1

    = S S1 .

    S

    0D =

    00

    , kD =

    0 k

    k 0

    ,

    5D =

    0

    0

    , kD =

    0 k

    k 0

    ,

  • 8/14/2019 (eBook) - Fisica Teorica

    88/214

    CD = i 2D 0D = i 2D = i

    0 2

    2 0

    ,

    0kD = i 0 k

    k 0 , ijD = ijk k 00 k ,

    0D 5D =

    0

    0

    , kD

    5D =

    k 00 k

    .

    2

    D

    D

    t+ + i m

    = 0 ,

    k

    2D M D 2M

    M = SM D S

    1M

    SM =1

    2

    D +

    2D

    =

    12

    0D +

    0D

    2D

    =

    12

    2

    2

    .

    SM = S1M = S

    M .

    M = SM D S1M =

    2D ,

    2M = SM 2D S

    1M = D .

  • 8/14/2019 (eBook) - Fisica Teorica

    89/214

    0M =

    0 2

    2 0

    , 1M =

    i3 0

    0 i3

    ,

    2M = 0 2

    2 0

    , 3M =i1 0

    0 i1

    ,

    1M =

    0 1

    1 0

    , 2M =

    00

    ,

    3M =

    0 3

    3 0

    , 5M =

    2 00 2

    ,

    CM = i 0M = i 0 2

    2 0

    .

    5

    5C = 0D

    0C = 5D

    C = SC D S

    1C ,

    SC =1

    2

    + 0D 5D

    =

    12

    SC = SC = S

    1C =

    12

    0D 5D=

    12

    .

    k

    kC = SC kD S

    1C =

    kD .

    CC = SC CD SC = i2 00 i2

    .

  • 8/14/2019 (eBook) - Fisica Teorica

    90/214

    0C =

    0

    0

    , kC =

    0 k

    k 0

    ,

    5C =

    00

    , kC =

    k 00 k

    ,

    CC = i

    2 00 2

    , kC =

    k 00 k

    .

  • 8/14/2019 (eBook) - Fisica Teorica

    91/214

    (x) a (x) = (x) B1 a B (x) = (x) B1 a B (x)T= (x) B a B1 (x) .

    BaB1

    B

    5 B1 = 5 ,

    B 5 B1 = B B1 5 = +0 5

    = 0 ,

    k 5 = k . ,

    B B1 = + = 0, =0 =0, = 0 ,

    =0, =0 . .

    a =

    (x) (x) = (x) B B1 (x) = (x) (x) .

    a =

    (x) (x) = (x) B B1 (x) = + (x) 0 (x) = 0 , (x) k (x)

    = k .

    a =

    (x) (x) = (x) B B1 (x)=

    +(x) (x)

    = 0, =0

    =0, = 0 ,(x) (x)

    =0, =0 .

  • 8/14/2019 (eBook) - Fisica Teorica

    92/214

    a = 5

    (x) 5 (x) = (x) B

    5

    B1 (x) =

    +(x) 0 5 (x)

    = 0 ,

    (x) k 5 (x)

    = k .

    a = 5

    (x) 5 (x) = (x) B 5 B1 (x) = (x) 5 (x) .

  • 8/14/2019 (eBook) - Fisica Teorica

    93/214

    L2

    ( p) =

    + 1

    ( p)

    L2

    2( + 1) 2( + 1)

    p

    L2

    2( + 1) p L2

    2( + 1)

    L2

    p

    L2

    ( p) = ( p) L2 +

    L2

    , p

    = 2

    ( + 1) ( p) + L2 , p .

    [LkLk, pj] = [Lk, [Lk, pj]] +

    2[Lk, pj]Lk

    [Lk, pj] = km[rm, pj]p = i

    kjp

    L2

    , p

    =

    k,j

    j

    Lk ,

    Lk , pj

    + 2

    Lk , pj

    Lk

    =

    k,jj

    2 kj kmpm + 2 i kjp Lk

    = 2 2 p + 2 ( p) L .

    k,

    kj km = 2 jm ,

    i

    j

    j jk = k k ,

  • 8/14/2019 (eBook) - Fisica Teorica

    94/214

    p L = 0

    L

    (1 )

    L2

    ,

    p = 2 2 ( p) .

    ( + 1) + 2 = ( + 1)

    L2

    ( p) = ( + 1) ( p) .

  • 8/14/2019 (eBook) - Fisica Teorica

    95/214

  • 8/14/2019 (eBook) - Fisica Teorica

    96/214

  • 8/14/2019 (eBook) - Fisica Teorica

    97/214

    (x)

    F A

  • 8/14/2019 (eBook) - Fisica Teorica

    98/214

    A(x) A(x) = A(x) + (x) .

    A(x) A(x)

    A(x)

    A(x)

    A = 0 .

    A

    A(x) = A(x) + (x) A

    (x) = 0 (x)

    (x) = A(x) .

    A(x)

    (x) = 0

    A = 0 .

    j = 0

    A(x) = 0 ,A0(x) = 0 .

    A(x) A(x) = A(x) (x) ,A0(x) A0(x) = A0(x) + 0(x)

    (x)

    (x) = A(x) = A(x) = 0 ,0(x) = A0(x) = A0(x) = 0 .

  • 8/14/2019 (eBook) - Fisica Teorica

    99/214

    A(x)

    A (A) = j

    j

    = 0

    = 0

    A0 0

    0A0 +

    A

    = 0 .

    A0 = 0 0

    A

    = 0

    A

    A0 = 0

    j = 0

    A0 = 0

    B =

    A ,

    E = A

    t,

    A

    A = 0 .

    A0 = 0

    A

    t = 0

    L

    V

    A

    A(0, x) =1V

    k

    =1,2

    ck,(0)

    ()(k) eikx

    uk,(x)

    +ck,(0)()(k) ei

    kx uk,

    (x)

    ,

    (1)(k)

    (2)(k)

    k

    ()(k)

    k

    (1)(k) (2)(k)

    ()(k) ()(k) = , ()(k) k = 0 .

    uk,(x)

    1

    V

    d3x uk,(x) uk,(x) = k, k

  • 8/14/2019 (eBook) - Fisica Teorica

    100/214

    Ek

    T(1)

    (2)

    (1)(k)

    (2)(k)

    Lk = 2 (n1, n2, n3) , ni = 1, 2, . . .

    A ck,(0)

    ck,(t) = ck,(0) ei t ,

    ck, + 2 ck, = 0 ,

    =

    2

    T = |k|c .

    A(t, x) =1V

    k

    =1,2

    ck,(0)

    ()(k) eikx + ck,(0)()(k) eikx

    ,

    k0 =

    H =1

    2

    d3x

    | E|2 + | B|2

    H =

    k

    =1,2

    2

    c

    2ck,(t) ck,(t) .

  • 8/14/2019 (eBook) - Fisica Teorica

    101/214

  • 8/14/2019 (eBook) - Fisica Teorica

    102/214

    A(t, x) =1V k =1,2 c

    2 ak,()(k) eikx + ak,

    ()(k) eikx .

    A

    E

    B

    E(t, x) =iV

    k

    =1,2

    c

    2

    ak,

    ()(k) eikx ak,()(k) eikx

    ,

    B(t, x) = iV k =1,2

    c

    2k

    ak,

    ()(k) eikx ak,()(k) eikx

    .

    H =1

    2

    k

    =1,2

    ak,ak, + ak,ak,

    =

    k =1,2

    ak,ak, +

    1

    2

    .

    ak,ak,

    k

    Nk,

    Nk, ak,ak, .

    nk1,1 (k1, 1) nk2,2

    (k2, 2)

    |nk1,1 , nk2,2 , . . . , nki,i , . . . .

    Nki,i nki,i

    Nki,i|nk1,1 , nk2,2 , . . . , nki,i , . . . = nki,i |nk1,1 , nk2,2 , . . . , nki,i , . . . .

  • 8/14/2019 (eBook) - Fisica Teorica

    103/214

    ak, ak,

    Nk,

    [ak, , Nk,] = k,k ak, ,

    [ak, , Nk,] = k,k ak, .

    (k, )

    k,

    N a|n = a N + a |n = (n + 1) a|n ,

    N a|n = (a N a) |n = (n 1) a|n .

    a

    a

    a

    ,

    a

    .

    a|n = c+|n + 1 , a|n = c|n 1 ,

    c+ c

    n |n = 1

    |c+|2

    = n|a a

    |n = n| a a

    a

    a [a,a]=1

    + a

    aN

    |n = n + 1 ,

    |c|2 = n| a aN

    |n = n .

    c+ c

    a|n = n + 1|n + 1 , a|n = n|n 1 .

    |0

    (k, )

    ak,|0 = 0 (k, ) .

    ak,

    |1k, = ak,|0 ,

  • 8/14/2019 (eBook) - Fisica Teorica

    104/214

    |1k, , 1 k, = ak,ak,

    |0 .

    (k, ) (k, )

    H

    H =

    k

    =1,2

    Nk, +

    1

    2

    .

    1

    2

    k

    =1,2

    H|0 = 12 k =1,2

    |0 .

    H =

    k

    =1,2

    Nk, = H|0 = 0 .

    P =1

    c

    d3x ( E B) .

    P

    E

    B

    P =

    k

    =1,2

    k

    Nk, +

    1

    2

    =

    k

    =1,2

    kNk, .

  • 8/14/2019 (eBook) - Fisica Teorica

    105/214

    H ak,|0 = ak,

    |0 ,

    P a

    k,|0 = k a

    k,|0 .

    E = = |k|c

    p = k

    m =1

    c2

    E2 p2c2 = 1

    c2

    2 2 2k2c2 = 0 .

    ()

    (1)

    (2)

    () = (1)

    i(2)

    2

    .

    Tx Ty Tz T1,m m = 0, 1 T1,1 =

    Tx i Ty2

    ,

    T1,0 = Tz ,

    ()

    m = 1 m = 0

  • 8/14/2019 (eBook) - Fisica Teorica

    106/214

  • 8/14/2019 (eBook) - Fisica Teorica

    107/214

    (x)

    = 1, . . . , N

    A(x)

    = 1, . . . , 4

    L = L(, )

    (x)

    x

    x(s) x(s)

    qs (t) = (t, s) (s = 1, 2, . . . ) ,

    (t, s) = (t, x(s)) L(t) =

    d3x L((x), (x))

    L(t) =

    s

    x(s) L(s) ,

    L(s) s qs (t)

    ps (t) =L

    qs (t)=

    L

    (t, s)=

    L(s)(t, s)

    x(s)

  • 8/14/2019 (eBook) - Fisica Teorica

    108/214

    H =

    s

    ps qs L .

    (t, s) L(s)(t, s)

    ps (t) = (t, s) x(s)

    H

    H =

    s

    x(s)

    (t, s) (t, s) L(s)

    .

    x(s) 0

    (t, s) (x)

    (t, s) L(x)

    (x) ,

    H(t) =

    d3x H(t, x) ,

    H(x) = (x) (x) L(x) .

    (x)

    (x)

    I()

    d4x L(, )

    (x) (x) +(x)

    I() = 0 .

    I() =

    d4x

    L

    +

    L()

    ()

    ()

    =

    d4x

    L

    +

    L

    ()

    L

    ()

    .

  • 8/14/2019 (eBook) - Fisica Teorica

    109/214

    d4x

    L

    ()

    =

    dSL

    () = 0 ,

    = 0

    0 = I() =

    d4x

    L

    L

    ()

    .

    L

    () L

    = 0 ( = 1, . . . , N ) .

    (x)

    L= a

    + b ,

    a

    b

    a () b = 0 .

    + m2

    = 0 ,

    b/a = m2 L

    a = 1/2

    L = 12

    1

    2m2 .

    N

    (x)

    = 1, . . . , N

    L = 12

    1

    2m2 ,

  • 8/14/2019 (eBook) - Fisica Teorica

    110/214

    (x)

    (+ m2) = 0 .

    (x)

    (x) =L

    (0 )= 0

    (x) ,

    H = 0 L= ()2 1

    2

    +1

    2m2

    =1

    2 ()2 + ()2 + m2()2 .

    L = 12

    a A

    A + b A A

    + c (A)2 + d AA

    .

    L

    A

    A (A) = 0 .

    L(A)

    = a A + b A + c g A

    ,

    L

    (A)= aA + (b + c) (A

    ) ,

    LA = d A .

    aA + (b + c) (A) d A = 0 .

    d = 0

    b + c

    a= 1 ,

  • 8/14/2019 (eBook) - Fisica Teorica

    111/214

    L = 12

    a A

    A a A A c A A + c (A)2

    .

    a

    L = 14

    FF +

    c

    2a

    A

    A (A)2

    [A(Ag A)]

    .

    [A (A

    gA)]

    L = 14

    FF .

    A F

    A(x) A(x) = A(x) + (x)

    L

    L

    AA

    d = 0

    A A

    L = 14

    FF +

    1

    2m2 AA

    (+ m2) A (A) = 0 .

    m2A

    12

    m2 AA

    A

    qs

    ps

    [qs , ps] = i ss ,

    [qs , qs ] = [p

    s , p

    s] = 0 .

    qs = (t, s)

    ps = (t, s) x(s) ,

  • 8/14/2019 (eBook) - Fisica Teorica

    112/214

    [(t, s) , (t, s)] = i ss

    x(s),

    [(t, s) , (t, s)] = [(t, s) , (t, s)] = 0 .

    x(s) 0 ss

    x(s)

    x(s)03(x x) ,

    x = x(s) x = x(s)

    fs =

    sx(s)

    ss

    x(s)fs

    x(s)0f(x) =

    d3x 3(x x) f(x) .

    [(t, x) , (t, x)] = i 3(x x) ,

    [(t, x) , (t, x)] = [(t, x) , (t, x)] = 0 .

    (x)

    (x)

    (x) = 0 (x) k0 = k =

    +k2 + m2

    (x) =1V

    k

    12k

    ak e

    ikx + ak eikx

    k0=k,

    (x) =i

    V

    k

    k2

    ak e

    ikx ak eikx

    k0=k.

    ak

    ak ak

    ak

    3(x x) = 1V

    k e

    ik(xx)

    [ak , ak] = k,k ,

    [ak , ak] = [ak

    , ak ] = 0 .

    ak ak

  • 8/14/2019 (eBook) - Fisica Teorica

    113/214

    H =1

    2

    d3x

    ()2 + ()2 + m2()2

    t=0

    = k kak ak +1

    2 ,

    H =

    k

    k Nk , Nk ak ak .

    (x) (+)(x) + ()(x) ,

    (+)(x)

    ,

    ()(x)

    .

    ((+)(x)) = ()(x) .

    [(x) , (x)] =1

    V

    k,k

    12k

    2k

    ak e

    ikx + ak eikx

    ,

    ak eikx + a

    k eik

    x

    k0=kk0=k

    =1

    V

    k,k

    12k

    2k

    [ak , a

    k ] ei(kxk

    x) + [ak , ak] ei(kxk

    x)

    k0=kk0=k

    =1

    V

    k

    1

    2k

    eik(xx

    ) eik(xx)

    k0=k

    V1

    (2)3

    d3k

    2k eik(xx)

    eik(xx

    )k0=k .

    (x) i(2)3

    d3k

    2k

    eikx eikx

    k0=k= 1

    (2)3

    d3k

    ksin(kx)|k0=k ,

    [(x) , (x)] = i (x x) .

    (x)

  • 8/14/2019 (eBook) - Fisica Teorica

    114/214

  • 8/14/2019 (eBook) - Fisica Teorica

    115/214

    T

    ERe k0

    Im k0

    k +k'& $%E

    '

    C

    C

    (x)

    C

    k

    1(2)4

    C

    d4keikx

    k2 m2 = 2i

    (2)4

    d3k

    lim

    k0k

    (k0 k) e

    ikx

    (k0 k)(k0 + k)

    + limk0k

    (k0 + k)

    eikx

    (k0 k)(k0 + k)

    =i

    (2)3

    d3k

    2k

    eikx eikx

    k0=k (x) .

  • 8/14/2019 (eBook) - Fisica Teorica

    116/214

  • 8/14/2019 (eBook) - Fisica Teorica

    117/214

    b(r)p , b

    (r)

    p

    = r,r p,p , b(r)p , b

    (r)

    p

    =

    b(r)p

    , b(r)

    p

    = 0 ,

    r

    b(r)p

    |0

    ,

    b(r)p

    b(r)

    p

    |0 . r = r p = p

    b(r)p

    b(r)p

    |0 = 12

    b(r)p

    , b

    (r)p

    |0 = 0 ,

    r,p=r,p

    b(r)p

    b(r)

    p

    |0 = b(r)p

    b(r)p

    |0 ,

    r,p r,p

    N(r)

    p b(r)p

    b(r)p ,

    N(r)p |0 = b(r)p

    b(r)p |0 = 0 , N

    (r)p (b

    (r)p

    |0) = b(r)p

    b(r)p b

    (r)p

    |0 = b(r)p

    (1 b(r)p

    b(r)p ) |0 = b(r)p

    |0 ,

    N(r)

    p

    2= b

    (r)p

    b(r)p b

    (r)p

    b(r)p = b

    (r)p

    (1 b(r)p

    b(r)p ) b

    (r)p = b

    (r)p

    b(r)p = N

    (r)p .

  • 8/14/2019 (eBook) - Fisica Teorica

    118/214

    N(r)

    p (N(r)

    p 1) = 0

    N(r)p

    L(x) = (x) (i c

    m c2) (x)

    = (x) (i c

    m c2) (x)

    L

    L

    L

    L

    = (i c

    mc2) (x) , L()

    = 0 ,

    (i c mc2) (x) = 0 ,

    (i

    m) (x) = 0 .

    L

    L

    = (x) (i

    m) , L()

    = 0 ,

    (x) (i

    +m) = 0 .

    L

    (x) =L

    = i 0 = i .

  • 8/14/2019 (eBook) - Fisica Teorica

    119/214

    L

    = 0

    H = i 0 (i 00 + i kk m) = (

    i

    + m)

    = (i + m) .

    H =

    d3x (i + m) .

    (x) =1V

    r=1,2

    p

    m

    E

    b(r)p u

    (r)(p) eipx + d(r)p v

    (r)(p) eipx

    p0=E.

    E +

    p2 + m2 (x) b d

    b

    d

    b(r)p p r

    d(r)p p r

    b

    d

    b(r)p , b

    (r)

    p

    =

    d(r)p , d

    (r)

    p

    = r,r p,p ,

    b(r)p , b

    (r)

    p

    =

    b(r)p , b

    (r)

    p

    =

    d(r)p , d

    (r)

    p

    =

    d(r)p , d

    (r)

    p

    = 0 ,

    b(r)p , d

    (r)

    p

    =

    b(r)p , d

    (r)

    p

    =

    b(r)p , d

    (r)

    p

    =

    b(r)p , d

    (r)

    p

    = 0 .

    (x)

    (x) = 1V

    r=1,2

    p

    mEd(r)p v(r)(p) eipx + b(r)p u(r)(p) eipx

    p0=E.

    H =1

    V

    d3x

    r,r

    p,p

    mEE

    d(r)p v

    (r)(p) eipx + b(r)p u

    (r)(p) eipx

    p0=E

    (i + m)

    b(r)

    pu(r

    )(p) eipx + d(r

    )

    pv(r

    )(p) eipx

    p0=E.

  • 8/14/2019 (eBook) - Fisica Teorica

    120/214

    (i + m) = i 0 i 0 eipx

    k0=E

    = E eipx

    k0=E

    ,

    H = 1Vr,r

    p,p

    mEE

    E d(r)p d(r)p v(r)(p) v(r)(p) d3xei(pp)x V p,p

    + b(r)p b

    (r)

    pu(r)(p) u(r

    )(p)

    d3xei(p

    p)x V p,p

    p0=Ep0=E

    u(r)(p) u(r)(p) = Em rr = v(r)(p) v(r)(p) ,

    H

    H =p,r

    E

    b(r)p b

    (r)p d(r)p d(r)p

    =p,r

    E

    b(r)p b

    (r)p + d

    (r)p d

    (r)p 1

    .

    b(r)p b

    (r)p N

    (r)p (e)

    d(r)p d

    (r)p N(r)p (e+)

    E

    p,r E

    H =p,r

    E

    N(r)

    p (e) + N

    (r)p (e

    +)

    .

    Q = e

    d3x

    = ep,r

    b(r)p b

    (r)p + d

    (r)p d

    (r)p

    = e

    p,r

    b(r)p b

    (r)p d(r)p d(r)p + 1

    .

  • 8/14/2019 (eBook) - Fisica Teorica

    121/214

    e = |e|

    Q = e

    p,r N

    (r)p (e

    ) N(r)p (e+)

    .

    P = i

    d3x

    =p,r

    p

    b(r)p b

    (r)p d(r)p d(r)p

    = p,r pb

    (r)p b

    (r)p + d

    (r)p d

    (r)p 1 .

    p p = 0

    P =p,r

    p

    N(r)

    p (e) + N

    (r)p (e

    +)

    .

    d(r)p |0 +p

    b(r)p |0

    {(x) , (x)} = (x) , (x) = 0 , (x) , (x

    )

    = i S(x x) ,

    S(x) =i

    (2)3

    d3p

    2E

    ( p + m) eipx + ( p m) eipx

    p0=E.

  • 8/14/2019 (eBook) - Fisica Teorica

    122/214

    (x) , (x

    )

    =

    =1

    V p,r p,rm

    EEu

    (r) (p) u

    (r) (p

    )b(r)p , b

    (r)

    p r,r p,pei(pxp

    x)

    + v(r) (p) v(r) (p

    )

    d(r)p , d(r)

    p

    r,r p,p

    ei(pxpx)

    p0=Ep0=E

    =1

    V

    p

    m

    E

    r

    u(r) (p) u(r) (p)

    (p+m)2m

    eip(xx) +

    r

    v(r) (p) v(r) (p)

    (pm)2m

    eip(xx)

    p0=E

    =

    1

    V p

    1

    2E( p + m) eip(xx) + ( p m) eip(xx)p0=E

    V

    1

    (2)3

    d3p

    2E

    (

    p + m) eip(xx) + (

    p m) eip(xx)

    p0=E

    i S(x x) .

    S(x)

    S(x)

    S(x) = i(2)3

    d4p (

    p + m) eipx (p0) (p2 m2) .

    i

    (2)3

    d4p (

    p + m) eipx (p0) (p2 m2) =

    =i

    (2)3

    d4p (

    p + m) eipx (p0)1

    2E[(p0 E) + (p0 + E)]

    =

    i

    (2)3d3p

    2E ( p + m) eipxp0=E d3p

    2E ( p + m) eipxp0=E d3p2E

    (

    p+m) eipxp0=E

    S(x) .

    S(x x)

    S(x x) = (i

    x + m) (x x) .

  • 8/14/2019 (eBook) - Fisica Teorica

    123/214

    (i

    x + m) (x x) ==

    i

    (2)3 d4p (i x + m) e

    ip(xx) (p0) (p2 m2)

    =i

    (2)3

    d4p (

    p + m) eip(xx) (p0) (p

    2 m2) S(x x) .

    (x x)

    S(x x) = 0

    (x) , (x)

    = 0

    (x x)2 < 0 .

    (x) (x)

    [L] =

    E

    3

    [m4] .

    1/2

    [E] [ ] =

    E3

    [] = 13/2

    [m3/2] .

    u

    v

    b

    d

    L = 12

    1

    c2

    t

    2

    2 1

    2

    m c

    22 ,

    [2] [2] = E3

    [] =

    E1/2

    1/2

    [m] .

    ak

  • 8/14/2019 (eBook) - Fisica Teorica

    124/214

  • 8/14/2019 (eBook) - Fisica Teorica

    125/214

    + i e A .

    LD

    LD = (i m) +i e A L = (i e A m) LD + LI ,

    LI = e A = e j A

    LI

    HI =

    LI

    + LI

    +LI

    A

    A

    LI .

    LI HI = LI = e A = e j A .

    Lem = 14

    F F

  • 8/14/2019 (eBook) - Fisica Teorica

    126/214

  • 8/14/2019 (eBook) - Fisica Teorica

    127/214

    HI = e

    (+)

    + ()

    (+) + ()

    A

    = e ()

    (+) A rrrre

    e

    + e (+)

    () A rrrr

    e+ e+

    + e (+)

    (+) A

    rrrre

    e+

    + e ()

    () A

    rrrre+

    e

    HI

    e

    e+

    e

    e+

    (+)

    u(r)(p)

    sp

    ()

    v(r)(p)

    sp

  • 8/14/2019 (eBook) - Fisica Teorica

    128/214

    ()

    u(r)(p)

    s

    p

    (+)

    v(r)(p)

    sp

    () ()

    ()

    ()

    (+) (x) , () (x) = 1V p

    12E

    (

    p + m) eip(xx)

    p0=E

    V

    1

    (2)3

    d3p

    2E(

    p + m) eip(xx)

    p0=E

    i S(+) (x x) ,

    () (x) ,

    (+)

    (x)

    =1

    V

    p

    1

    2E(

    p m) eip(xx)p0=E

    V1

    (2)3 d3p

    2E

    (

    p

    m) e

    ip(xx)p0=E i S() (x x) .

    (x) , (x

    )

    =

    (+) (x) , ()

    (x)

    +

    () (x) , (+)

    (x)

    = i

    S(+) (x x) + S() (x x)

    = i S(x x) .

  • 8/14/2019 (eBook) - Fisica Teorica

    129/214

    S

    |n1, n2, . . . , ni, . . . (n1, n2, . . . , ni, . . . ) ,

    n1, n2, . . . , ni, . . . |n1, n2, . . . , ni, . . . = ((n1, n2, . . . , ni, . . . ) , (n1, n2, . . . , ni, . . . ))

    =

    i

    ni,ni .

    t =

    t = +

    H0

    t =

    t = +

    HI

    &&

    &&

    &&

    &&

    &b

    ~

    e(pi, r) e(pf, s)

    (ki, ) (kf, )

  • 8/14/2019 (eBook) - Fisica Teorica

    130/214

    HI = e j

    A .

    S(t)

    i

    tS(t) = HS S(t) = (HS0 + H

    SI )

    S(t) .

    (t)

    (t)

    S(t)

    S

    (t) = eiHS0 t S(t) ,

    (t) = eiHS0 t S eiH

    S0 t .

    (t)

    i

    t(t) = HS0 eiH

    S0 t S(t) + eiH

    S0 t i

    tS(t)

    = HS0 eiHS0 t S(t) + eiH

    S0 t (HS0 + H

    SI )

    S(t)

    = eiHS0 t HSI e

    iHS0 t eiHS0 t S(t) HI(t) (t) ,

    (t)

    d(t)

    dt= i HS0 e

    iHS0 t S eiHS0 t i eiHS0 t S eiHS0 t HS0

    = i [HS0 , (t)] = i [H0 , (t)] ,

    HI(t) = eiHS0 t HSI e

    iHS0 t ,

    H0 = eiHS0 t HS0 e

    iHS0 t = HS0 .

  • 8/14/2019 (eBook) - Fisica Teorica

    131/214

    S

    U

    (t) = U(t, t0) (t0) , U(t0, t0) = 1 ,

    i

    tU(t, t0)

    (t0) = HI(t) U(t, t0) (t0) .

    (t0)

    U(t, t0) = 1 it

    t0

    dt HI(t) U(t, t0) .

    U(t, t0) = 1 it

    t0

    dt1 HI(t1)

    1 i

    t1t0

    dt2 HI(t2) U(t2, t0)

    = 1 i

    tt0

    dt1 HI(t1) + (i)2t

    t0

    dt1

    t1t0

    dt2 HI(t1) HI(t2) + . . .

    . . . + (i)n tt0

    dt1 t1t0

    dt2 . . .tn1t0

    dtn HI(t1) HI(t2) . . . H I(tn) + . . . .

    i t0 (t) t

    (t) = U(t, t0) i .

    t

    f

    (f , (t)) = (f , U(t, t0) i) Ufi(t, t0) .

    i

    f

    Pf i =|Ufi(t, t0) fi|2

    t t0 .

    ()

    (+)

    t =

    t = +

    ()

    (+)

    U

    (+) = U(+, ) () S() ,

  • 8/14/2019 (eBook) - Fisica Teorica

    132/214

    S U(+, )

    S= 1 i+

    dt1 HI(t1) + (i)2+

    dt1

    t1

    dt2 HI(t1) HI(t2) + . . .

    1 +

    S(1) +

    S(2) + . . .

    =

    n=0

    (i)n+

    dt1t1

    dt2 . . .tn1

    dtn HI(t1) HI(t2) . . . H I(tn) .

    S

    S(2)

    S(2) = (i)2+

    dt1

    t1

    dt2 HI(t1) HI(t2) ,

    S(2)

    S(2) = (i)2 +

    dt1 +t1

    dt2 HI(t2) HI(t1) .

    HI

    H0

    t1 t2

    S(2) = (i)2+

    dt2

    t2

    dt1 HI(t2) HI(t1) .

    t1 t2 t2 > t1

    S(2)

    S(2) = (i)2+

    dt1

    +t1

    dt2 HI(t2) HI(t1) ,

    S(2)

    S(2) = (i)2

    2 +

    dt1

    t1

    dt2 (HI(t1) HI(t2)) +

    +

    t1

    dt2 (HI(t2) HI(t1))

    =

    (i)22

    +

    dt1+

    dt2 P[HI(t1) HI(t2)]

    =(i)2

    2

    d4x1

    d4x2 P[HI(x1) HI(x2)] ,

    P[(x) (x)] =

    (x) (x)

    x0 > x0 ,

    (x) (x)

    x0 > x0 .

  • 8/14/2019 (eBook) - Fisica Teorica

    133/214

    T

    Et1

    t2

    T

    Et1

    t2

    S(2)

    P

    S(n)

    S(n) = (i)n

    n!

    +

    dt1+

    dt2 . . .+

    dtn P[HI(t1) HI(t2) . . . H I(tn)]

    =(i)n

    n!

    d4x1

    d4x2 . . .

    d4xn P[HI(x1) HI(x2) . . . HI(xn)] .

    S

    S=

    n=0

    (i)nn!

    d4x1

    d4x2 . . .

    d4xn P[HI(x1) HI(x2) . . . HI(xn)] .

    S

    S S = S S=

    ,

    n

    Sfn Sin =

    n

    Snf Sni = fi ,

    N

    (+)()

    = ()(+) , N

    ()(+)

    = ()(+) ,

    N

    (+)(+)

    = (+)(+) , N

    ()()

    = ()() ,

  • 8/14/2019 (eBook) - Fisica Teorica

    134/214

    N[] = N

    (+) + ()

    (+) + ()

    = (+)(+) + 2()(+) + ()() .

    N

    (+) ()

    = () (+) , N

    (+)

    ()

    = () (+) ,

    N

    (+)

    ()

    = ()

    (+)

    , N

    (+) ()

    = () (+) ,

    () ()

    N = N(+)

    + ()

    (+) +

    ()

    = (+)

    (+) +

    ()

    (+) ()

    (+)

    + ()

    () .

    N

    () (+)

    (+)

    +

    TT

    ()

    =

    ()

    ()

    (+)

    (+)

    = ()

    ()

    (+)

    (+) .

    N () (+) (+) JJ

    RR

    () = () () (+) (+) .

    N[A1A2 . . . An] = (1)PB1B2 . . . Bn ,

    P

    B1B2 . . . Bn

    A1A2 . . . An

    : AB : N[AB] .

    0|N[A1A2 . . . An]|0 = 0 ,

  • 8/14/2019 (eBook) - Fisica Teorica

    135/214

  • 8/14/2019 (eBook) - Fisica Teorica

    136/214

  • 8/14/2019 (eBook) - Fisica Teorica

    137/214

    e2/4

    1 137

    T[A(x1)B(x2)] = (x01 x02)A(x1)B(x2) (x02 x01)B(x2)A(x1)

    =